Given a computer with a memory system having a32_bit address, a cache consisting of 4096 blocks each is 8 words. For the following cache types: Direct Mapped (DM). Fully associative (FA), Four_way set associative (4_way), calculate the following values as specified. (Use paper and pencil to do needed calculations and write the final answer in the given blank space). 1. The size of the offset field =Blank 1bits 2. DM: size of the index field =Blank 2bits 3.4_way: size of the Index field - Blank 3bits 4. DM: The number of sets Blank 4 5.4_way. The number of sets - Blank 5 6. FA: The number of sets Blank 6 7. DM: The size of the tag field Blank bits 8. 4_way. The size of the tag field =Blank 8bits 9. FA: The size of the tag field =Blank 9bits 10. FA: The total size of tag bits in the cache =Blank 10kbits