Given a string $s$ of lowercase English characters, find out whether the summation of $x$ and $y$ is even or odd, where $x$ is the count of distinct characters that occupy even positions in English alphabets and have even frequency, $y$ is the count of distinct characters which occupy odd positions in English alphabets and have odd frequency.

Note: Positive means greater than zero.

Example $1$:

Input:

$s=$ abbbcc

Output:

ODD

Explanation:

$x=0$ and $y=1$ so $(x+y)$ is ODD. $\text{'}$a$\text{'}$ occupies $1$st place$($odd$)$ in english alphabets and its frequency is odd$(1),\text{'}$b$\text{'}$ occupies $2$nd place$($even$)$ but its frequency is odd$(3)$ so it doesn't get counted and $\text{'}$c$\text{'}$ occupies $3$rd place$($odd$)$ but its frequency is even$(2)$ so it also doesn't get counted.

Example $2$:

Input:

$s=$ nobitaa

Output:

EVEN

Explanation:

$x=0$ and $y=2$ so $(x+y)$ is EVEN.

Your Task:

You don't need to read input or print anything. Complete the function evenodd$()$ which takes s as input parameter and returns "EVEN" if $x+y$ is even, and returns "ODD" otherwise.

Expected Time Complexity: $O(|s|)$

Expected Auxiliary Space: $O(1)$

Constraints:

$1|s|{10}^5$