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Given: /bar (PQ)|(| |)/( b)ar (ST)(;)/(b)ar (PR)~()/(b) | =ar (RT) Prove: /_(/)PQR~()/(_(/))=TSR Statements Reasons /bar (PQ)|(| |)/( b)ar (ST)(;)/(b)ar (PR)~()/(b) | =ar (RT)
Given:\
/bar (PQ)|(|
|)/(
b)ar (ST)(;)/(b)ar (PR)~()/(b)
|
=ar (RT)
\ Prove:
/_(/)PQR~()/(_(/))=TSR
\ Statements\ Reasons\
/bar (PQ)|(|
|)/(
b)ar (ST)(;)/(b)ar (PR)~()/(b)
|
=ar (RT)
1. Given\
/_(R)TS~()/(_(R))=PQ
\ (hint
/bar (TP)
is a transversal)\
/_(T)SR~()/(_(R))=QP
\ hint
/bar (SQ)
is a transversal)\
/_(/)PQR()/(_(/))TSR
\
\\\\Delta
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