Given below is the size distribution of crushed leach feed material. Using the size distribution and Rosin Rammler equation shown below to determine the parameter $b$ and $n$ for the equation. Where $P$ is the percent of material passing the screen of size $x,d$ is the screen size, $b$ is the absolute size constant, and $n$ is the size distribution constant.

$log[ln(\frac{100}{100-P})]=logb+nlogd$

$\backslash$table$[[\backslash$table$[[$Screen Size$],[($Inches$)]],\%$ Weight$],[1\mathrm{.}5,0\mathrm{.}9],[1,6\mathrm{.}0],[0\mathrm{.}75,18\mathrm{.}3],[0\mathrm{.}5,12\mathrm{.}1],[0\mathrm{.}375,15\mathrm{.}8],[0\mathrm{.}25,23\mathrm{.}6],[0\mathrm{.}0787,11\mathrm{.}1],[0\mathrm{.}0059,5\mathrm{.}7],[-0\mathrm{.}0059,6\mathrm{.}6]]$

Note the equation on slides is in terms of fraction of material passing, the current equation is in terms percent material passing.