Given! modulus of rigially mer dianeter = 40 mm GAB : 27 6Pa rodAB = aluminum 6BD : 39 6 Pa rod BD = brass RTB = 1200 N'm 60 mm TA= 600 N.m 90 mm where ! 36mm TBC 9 T CD A R 250 mm 1800 N- M = 600+ 1200 375 mm 2 1800 400 mm SOLUTION : TAB (LAB ) T Be ( L BC ) JCD ( LCD ) GJ + GAB JAB GBC JBC GBD JCD 600 * 0-4 1800 *0.3-75 27 *10 9 x 71 + 1800 x0- 250 32 x (0-036 ) 39 * 16 " x 7 - X (0 - 06 ) 32 x 3 9 *10 9 x TI x 32 OA= 0.0788 rad x 180 [ (0-06 ) - 60 - 04 ) 4 ] TT converting to degrees # 2 . ) DA = 4:515 0 answer 400 mm 375 mm 250 mm A 1.) TORSION DIAGRAM . ON . M MOMENT ( - ) B C D 600 N. m ( - ) 1800 N .m