Given N(80, 20), find the value of X that has 80% of the area bounded by the normal curve to its left. (Round the answer upto 2 decimal places) Table for required value of z Table for areas under thestandard normal curve X 00 .01 .02 .03 .04 .05 .06 .07 .08 09 0.0 .0000 .0040 .0080 .0120 .0160 1.0199 .0239 .0279 .0319 .0359 0.8 .2881 .2910 .2939 .2967 .2995 .3023 .3051 .3078 .3106 .3133 0.9 .3159 .3186 .3212 .3238 .3264 .3289 .3315 .3340 .3365 .3389 1.0 .3413 .3438 .3461 .3485 .3508 .3531 .3554 .3577 .3599 .3621 1.1 .3643 .3665 .3686 .3708 .3729 .3749 .3770 .3790 .3810 .3830 1.2 .3849 .3869 .3888 -3907 .3925 .3944 .3962 .3980 .3997 .4015 1.3 .4032 .4049 .4066 .4082 .4099 .4115 -4131 -4147 .4162 .4177\fSubmit Assess 50243Explfr Weight Given the following frequency table, draw the Cumulative Frequency Polygon (Ogive). Classes 0- 30 30 - 60 60 - 90 90 - 120 Frequency 10 12 13 Click here to enter answer Choose the Answer y'A Cumulative Frequency Polygon Cumulative Frequency Polygon Cumulative Frequency Polygon (120, 42) (120, 40) (120, 40) 40 (90, 29) 40 (90, 30) 40 (80, 29) 30 30 30 25 25 25 (60, 22) (60, 20) (60, 20) 20 20 15 15 15 10 10 (30, 10) (30, 12) (20, 10) 5 5 un 30 60 90 120 X 0 30 60 90 120 30 60 90 120 XFind the shaded areas under the following standard normal curves. = = 0 0.20 Table for areas under the standard normal curve X Z 2 .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .0000 .0040 .0080 .0120 .0160 .0199 .0239 .0279 .0319 .0359 0.2 .0793 .0832 .0871 .0910 -0948 .0987 -1026 .1064 .1103 .1141Using the areas in Figure (the Empirical Rule), find the areas between z = - 2 and z = 3 Done 0.1359 0.1359 0.3413 0.0215 10.3413 0.0215 -3 -2 -1 :=0 1 2 3