Given: NA = 6.022x1023 atoms/mole, Density, dCu= 8940 kg/m3,M= 63.5 g/mol, ( h = 6.626x10-34 J.s, me= 9.1x10- 31 kg)

IV Given: NA=6.0221023 atoms /mole, Density, dCu=8940kg/m3,M=63.5g/mol,(h=6.6261034J.s,me=9.110 31kg) (a) Calculate the No. of valence electrons (nCu) units: n/m3 (5 points) (b) Calculate the Fermi energy (in eV ) at EF@3000K (Given: kT=0.0258eV for 3000K ), you need to first calculate the Fermi energy (in eV ) of Cu at EF@0K. and use this for calculation at higher temperature. (5 points) (c) Calculate the density of states ( gEF@300K ) as states per J1m3 (5 points) nCu=(Valence)xMCuNAxdCuEF0(Cu)=8meh2(3n)32EF300K(Cu)=EF0(Cu)[1122(EFO(Cu)kT)2leVg(E)=(821/2)(h2me)3/2E1/2useEF300KinJoules The equations are given