Given R$=\{$A$,$B$,$C$,$D$,$E$\}$

If AB$>$C$,$ AB$>$D$,$ A$>$E$,$

Transforming the relation R to $3$NF and identify the PKs for each resulting relation. Which is the correct transformation?

R$1=\{$A$,$B$,$C$\},$ PK$=\{$A$\}$

R$2=\{$A$,$B$,$D$\},$ PK$=\{$A$\}$

R$3=\{$A$,$E$\},$ PK$=\{$A$\}$

R$1=\{$A$,$B$,$C$,$D$\},$ PK$=\{$A$,$B$\}$

R$2=\{$A$,$E$\},$ PK$=\{$A$\}$

R$1=\{$A$,$B$,$C$\},$ PK$=\{$A$,$B$\}$

R$2=\{$A$,$B$,$D$\},$ PK$=\{$A$,$D$\}$

R$3=\{$A$,$E$\},$ PK$=\{$A$\}$

R$1=\{$A$,$B$,$C$\},$ PK$=\{$A$,$B$\}$

R$2=\{$A$,$B$,$D$\},$ PK$=\{$A$,$B$\}$

R$3=\{$A$,$E$\},$ PK$=\{$A$\}$