Given that: rocess capacity of a step = number of resources x 60/ time taken to serve one customer Capacity of A = 2 x 60/3 = 40 per hour Capacity of B =60/2 =30 per hour Capacity of C = 60/3 =20 per hour Capacity of D = 15 per hour Capacity of series combination of B and C = Min [ capacity of B, capacity of C] = MIn [ 30,20] =20 per hour Since this combination works in parallel with D, the slower of the two would determine the process capacity. Rate at which units reach E = Min [ capacity of D, capacity of series combination of B and C] = Min [ 15,20] =15 per hour Capacity of E = 1x60/1=60 per hour The slowest resource which restricts process capacity is D with an output of 15 per hour Process bottlenck -D Process capacity = 15 per hour Cycle time = 60/15 =4 min Flow time= sum of task times = time taken by A Max [ time taken by D, Time taken by B and C] Time taken by E = 3 2 3 1 =9 min Demand rate = 60/5 =12 per hour