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Given the following at 25deg C and 1.00atm : (1)/(2)N_(2)(g)+O_(2)(g)->NO_(2)(g),Delta Hdeg =33.2kJ N_(2)(g)+2O_(2)(g)->N_(2)O_(4)(g),Delta Hdeg =11.1kJ Calculate the Delta Hdeg for the reaction below at
Given the following at
25\\\\deg C
and
1.00atm
:\
(1)/(2)N_(2)(g)+O_(2)(g)->NO_(2)(g),\\\\Delta H\\\\deg =33.2kJ\ N_(2)(g)+2O_(2)(g)->N_(2)O_(4)(g),\\\\Delta H\\\\deg =11.1kJ
\ Calculate the
\\\\Delta H\\\\deg
for the reaction below at
25\\\\deg C
.\
2NO_(2)(g)->N_(2)O_(4)(g)
\ a.
-22.1kJ
\ b.
11.0kJ
\ c.
+53.3kJ
\ d.
-55.3kJ
\ e.
+44.3kJ
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