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Given the following beam with the following cross-section and with the moment (M) shear (S) and axial (N) diagram. F = P Ma =
Given the following beam with the following cross-section and with the moment (M) shear (S) and axial (N) diagram. F = P Ma = 1 000 P mm F1 = 2P d = 500 mm L= 1000 mm N [P] -2 S [P] -1 M [P mm] -500 -1000 A b = 30 mm B y= 23.5 mm | G t = 2 y F a=15 mm c = 40 mm C Figure 1: Schematics for problem 4. The expressions for the Moment (M), Shear (S), and Axial (N) are as follows (units in [P] and [Pmm]): N(2) = 2 S(z) M(z): if z 500 -1 = if z 500 -500 - z -1000 if 500 = if z 500 If the centroid of the given cross-section is at y = 23.5mm, the area is A = 162mm and the moment of inertia at the centroid is Ixx = 38290mm 4: 1. Calculate expressions that represent how the direct stress (xx) varies with z at points A, B, C, D, E, F and G. 2. Plot the expressions you found in the previous problem to see how the direct stress (xx) varies with z at those points.
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