given the number 123456789, is it possible to find a permutation such that the left most digit is evenly divisible by 1, the two left most digits are evenly divisible by 2, the three left most digits are divisibly by 3 and so on? For example, in 123456789, 1 is evenly divisible by 1, 12 is evenly divisible by 2, 123 is evenly divisible by 3, but because 1234 is not evenly divisible by 4 this number is not a solution to the question. Second, is it possible to find a similar permutation given the number 1234567890? Finally, is it possible to find a similar permutation for any of the given hexadecimal numbers, 1234567890AB, 1234567890ABC, 1234567890ABCD, 1234567890ABCDE, 1234567890ABCDEF?