Given the two charged particles shown in the figure below, find the electric field at the origin. (Let q1 = -22.00 nC and 92 = 2.00 nC. Express your answer in vector form.) E N/C y (cm) 91 4 Not x (cm) -4 -2 2 4 -2 =4 Submit Answer 2. [-/5 Points] DETAILS KATZPSE1 24.P.013.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A small sphere with charge qA = +5.10 UC is at the origin, and a second sphere with charge qg = -4.20 UC is located at x = 2.10 m. At what finite distance from the origin is the electric field equal to zero? Xf = m Need Help? Master It Submit AnswerSo[ n ) . ( 1, 4) ( - 1 , 3 ) 2 1 I (0,0 ) - y - 2 2 ix ( cm ) 4 - 2 - 4 + Position vector of charge , relative to origin' 0' is. Position vector of charge 12 relative to origin '0 is . 72 = (- 2 + 3 ) ) X 102 m So the electric field at the origin ' O' due to charge V, 18 , - 2 ( 8 - 8 ) 18,13 = Also the electric field at O due to the charge V's is , yX9 . 18 , 13 ( 0 - 7 2 ) Vz ( 1 - 37 ) 10 ( JTO ) 2So the Net electric field at the origin ' 0' is , E = ET E V 2 = + UTE. (TO J z ( 2 - 3] ) Kid 16 - 9 22 X 10 + 2 113 ) ? + 4 ] ) ( VTO 1 3 = 9x 10 x lo 5 22 8 8 + + 6 17517 1ofto E = ( 3 3 940 . 37) 1 + ( 95 916 7 7 ) J ( N ) This is the required expression for electric field at the origin O