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Given this piece of code fragment: for ( int x = 0 ; x < 1 0 ; x + + ) { if (
Given this piece of code fragment:
for int x ; x ; x
if x
cout OK endl;
else
cout No endl;
Assuming the branch prediction by default is "TAKEN", what is the prediction of the cout OK statement inside the if branch when we use a bit branch history? T for taken, N for not taken
Question options:
NNNNN TTTTT
TNNNN NTTTT
TTNNN NNTTT
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