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Good evening, I need answers for the questions listed below please. If you need to use an excel sheet or a calculator, please do whatever

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Good evening, I need answers for the questions listed below please. If you need to use an excel sheet or a calculator, please do whatever works for you. I also write good reviews!

1.) A-D?

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Using the TI-84 calculator, find the area under the standard normal curve. Round the answers to four decimal places. (a) Find the area under the standard normal curve to the right of z = - 2.17. (b) Find the area under the standard normal curve that lies between z = -0.82 and z = -0.42. (c) Find the area under the standard normal curve that lies outside the interval between z = - 1.11 and z = 2.38. (d) Find the area under the standard normal curve to the left of z = - 1.30. Part: 0 / 4 Part 1 of 4 The area to the right of z = -2.17 isUse the TI84 calculator to find the zscores that bound the middle 84% of the area under the standard normal curve. Enter the answers in ascending order and round to two decimal places. The z-scores for the given area are D and D. Check our blood pressure: In a recent study, the Centers for Disease Control and prevention reported that diastolic blood pressures of adult women in the United States are approximately normally distributed with mean 80.3 and a standard deviation of 9.7- Round the answers to four decimal places. (a) 1What proportion of women have blood pressures lower than 64? The proportion of women who have blood pressures lower than 64 is E] . Electricity bills: According to a government energy agency, the mean monthly household electricity bill in the United States in 2011 was $109.38. Assume the amounts are normally distributed with standard deviation $23.00. Use the "IT84 Plus calculator to answer the following. (a) What proportion of bills are greater than $129? {b} What proportion of bills are between $36 and $140? (c) What is the probability that a randomly selected household had a monthly bill less than $120? Round the answers to at least four decimal places. The proportion of bills that are greater than $129 is D. The proportion of bills that are between $86 and $140 ism . The probability that a randomly selected household had a monthly bill less than $120 is D. Tire lifetimes: The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed with mean u = 39 and standard deviation 5 = 6. Use the 1184 Plus calculator to answer the following. (a) Find the 22nd percentile of the tire lifetimes. (b) Find the 74th percentile of the tire lifetimes. (c) Find the third quartile of the tire lifetimes. (d) The tire company wants to guarantee that its tires will last at least a certain number of miles. What number of miles (in thousands) should the company guarantee so that only 5% of the tires violate the guarantee? Round the answers to at least two decimal places. A sample of size 126 will be drawn from a population with mean 26 and standard deviation 3. Use the T[83 Plus'l84 Plus calculator. (3) Find the probability that ; will be more than 25. Round the answer to at least four decimal places. The probability that E will be more than 25 is [:1 . A sample of size 6 will be drawn from a normal population with mean 63 and standard deviation 12. Use the 1184 Plus calculator. (a) Is it appropriate to use the normal distribution to nd probabilities for E? (b) Find the probability that ; will be between 53 and 73. Round the answer to at least four decimal places. d _ (c) Find the 83r percentile of 1:. Round the answer to at least two decimal places. 0 It is appropriate to use the normal distribution to find probabilities for E. The probability that E will be between 53 and 73 is D. The 83rd percentile of; is D. Q It is not appropriate to use the normal distribution to find probabilities for E. Watch your cholesterol: The mean serum cholesterol level for U.S. adults was 200, with a standard deviation of 40 (the units are milligrams per deciliter}. A simple random sample of 108 adults is chosen. Use the 1184 calculator. Round the answers to four decimal places. What is the probability that the sample mean cholesterol level is greater than 208? The probability that the sample mean cholesterol level is greater than 208 is D. What is the probability that the sample mean cholesterol level is between 188 and 196? The probability that the sample mean cholesterol level is between 188 and 196 is D . Would it be unusual for the sample mean to be less than 194? It (Choose one) 1' be unusual for the sample mean to be less than 194, since the probability is D. Coffee: The National Coffee Association reported that 61% of U.S. adults drink coffee daily. A random sample of 250 U.S. adults is selected. Round your answers to at least four decimal places as needed. Part: 0 / 6 Part 1 of 6 (a) Find the mean JA. The mean LA isBlood pressure: High blood pressure has been identied as a risk factor for heart attacks and strokes. The proporb'on of U.S. adults with high blood pressure is 0.3. A sample of 42. U.S. adults is chosen. Use the TI84 Plus Calculator as needed. Round the answer to at least four decimal places. Is it appropriate to use the normal approximation to nd the probability that more than 45% of the people in the sample have high blood pressure? It {Choose one) 7 appropriate to use the normal curve, since Hp = D - (Choose one) 1' 10 and H(l p) = C] Complete the following sentences. Part: 0 / 2 Part 1 of 2 If * is a binomial random variable and if np > 10 and n (1-p) = 10, then X is X 5 approximately normal with ux = (Choose one) V and Or = np (1 -p) npFind the critical value z , needed to construct a confidence interval with level 87%. Round the answer to two decimal places. The critical value for the 87% confidence level isA population has standard deviation o = 17.4. Part 1 of 2 (a) How large a sample must be drawn so that a 98% confidence interval for u will have a margin of error equal to 3.8? Round the critical value to no less than three decimal places. Round the sample size up to the nearest integer. A sample size of is needed to be drawn in order to obtain a 98% confidence interval with a margin of error equal to 3.8. Part 2 of 2 (b) If the required confidence level were 99.9%, would the necessary sample size be larger or smaller? (Choose one) V because the confidence level is (Choose one) Larger X SmallerBaby talk: In a sample of 69 children, the mean age at which they first began to combine words was 16.44 months, with a standard deviation of 9.43 months. Part: 0 / 2 Part 1 of 2 Construct a 98% interval for the mean age at which they first begin to combine words. Round the answers to two decimal places. A 98% confidence interval for the mean age isSleeping outlier: A simple random sample of eight college freshmen were asked how many hours of sleep they typically got per night. The results were 8.5 7.5 6.5 9 24 6 8.5 8 Send data to Excel Notice that one joker said that he sleeps 24 a day. Part: 0 / 3 Part 1 of 3 (a) The data contain an outlier that is clearly a mistake. Eliminate the outlier, then construct a 90% confidence interval for the mean amount of sleep from the remaining values. Round the answers to at least two decimal places. A 90% confidence interval for the mean amount of sleep from the remaining values isVolunteering: The General Social Survey asked 129'? people whether they performed any volunteer work during the past year. A total of 530 people said they did. (a) Find a point estimate for the proportion of people who performed volunteer work during the past year. Round the answer to at least three decimal places. The point estimate for the proportion of people who performed volunteer work during the past year is E]

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