Government regulations dictate that for any production process involving a certain toxic chemical, the water in the output of the process must not exceed 7840 parts per million (ppm) of the chemical. For a particular process of concern, the water sample was collected by a manufacturer 16 times randomly and the sample average x was 7912 ppm. It is known from historical data that the standard deviation o is 120 ppm. Complete parts (a) and (b) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) What is the probability that the sample average in this experiment would exceed the government limit if the population mean is equal to the limit? Use the Central Limit Theorem. The probability is 0.5 . (Round to four decimal places as needed.) (b) Is an observed x = 7912 in this experiment firm evidence that the population mean for the process exceeds the government limit? Answer your question by computing P (X 2 7912 | u = 7840) . Assume that the distribution of the concentration is normal. Since P (X 2 7912 | | = 7840) = negligible, the observed x evidence that the population mean for the process exceeds the government limit. (Round to four decimal places as needed.)