h h The following data are recorded by one group of students: L = 73.69 mm; W = 74.69 mm; H = 38.87 mm; m = 171.17 g Predict h', the "height" of the wooden block under water, in mm. The answer should have four significant figures. Your Answer:Case 2 - A Floating Object (Pobj - Priq) B = F B= AT Ing Poly = F = mg water4. Determine the fraction of the volume of the block submerged under the water to its total volume. (You may put a rubber band around the block to mark the water line.) Place the woodblock in water and measure h' as shown in the graph. If the water line is tilted, take the average of the h and has h . h' = 26. 68 Calcuate sub / Voti = h' / hm 0- 6912 5. Does potj / Pw = Vsub/ Vobj ? What is the percentage difference? 2.43%%1. Determine the volume of the wooden block in m. ! = 74.03 mm = 0.07403 m; W= 74.62 mm = 0 . 07462 m; h = 38.60 mm = 6.03860 m; V = 2.13 x 10 4 m3 2. Determine the mass the of block and its density: M= 151.15 g= 0. 15115 kg Pobj = 709. 6 kg/m3 3. What is the ratio of the density of the block to the density of water? Pobj / pw= 0.709 6