Hand written solution required

1. Assume that the solar intensity, To, close to earth's surface is 1000W/m. In the figure below, it shows that earth's rotation axis is 23.5" with respect the vertical (ie: normal to orbit plane of earth). The summer solstice, June 21", has the axis tilted closest toward the sun. What is the solar intensity, ITs, at Thunder Bay (latitude: 48.4' above the equator) at this date? For example, at summer solstice the equator (latitude (), would have solar intensity: Is = 1000 cos(23.5')W/m? = 917W/m?. We ignore absorption in atmosphere and other effects here. Please show your work to get full marks. (a) 399 W/ma. (b) 907 W/m?. (c) 664 W/m. (d) 310 W/m. (e) None of the above. Axis Thunder Bay 23 6 66.50 Equator