Having trouble figuring this out. It needs to be done in Python and follow the pseudocode.

Implement the following algorithm to construct magic n x n squares; it works only if n is odd. : Here is the 5 x 5 square that you get if you follow this algorithm Set row -n -1, column - n/2. For k-1...n *n Place k at [row][column] Inerement row and column. If the row or column is n, replace it with 0. If the element at [row][column] has already been filled 11 18 25 2 9 10 12 19 213 4 6 13 20 22 23 57 14 16 17 24 1 8 15 Set row and column to their Drevious values, Decrement row. Write a program whosd input is the number n and whose output is the magic square of order n if n is odd