HB$($feed vapor$)=31\mathrm{.}1$ kj$/$mol

HT$($feed vapor$)=35\mathrm{.}55$ kj$/$mol

HB$($product vapor$)=30\mathrm{.}17$ kJ$/$mol

HT$($product vapor$)=4\mathrm{.}38$ kJ$/$mol

Calculate the heat removed by the process using the energy balance

equation.Q$=-2,172$ kJ$/$s The answers are listed please show me how to get them!

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