he isomerization of butane from a trans to the gauche conformational state has an equilibrium constant of approximately K = [gauche]/[trans] = 0.6 at 300 K.

Since there are two gauche conformers but only one trans conformer, we may approximate this isomerization reaction as a two level system in which the trans state has an energy of _t and a degeneracy of g_t=1, and the gauche state has an energy of _g and a degeneracy of g_g =2.

(5 pts) Use the above information to estimate the energy difference (kJ/mol) between the gauche and trans states = _{g t}?Answer 3.00230021273-1273

(5 pts) If =3001.5 J/mol, at what temperature (K) do you expect the equilibrium constant to be equal to 1?Answer 450522550600

(5 pts) What value will the equilibrium constant approach at very low temperature?Answer 00.512

(5 pts) What value will the equilibrium constant approach at very high temperature?Answer 00.512

[20 pts] The isomerization of butane from a trans to the gauche conformational state has an equilibrium constant of approximately K= [gauche] /[ trans] =0.6 at 300 K. Since there are two gauche conformers but only one trans conformer, we may approximate this isomerization reaction as a two level system in which the trans state has an energy of t and a degeneracy of gt=1, and the gauche state has an energy of g and a degeneracy of gg=2. 1. (5 pts) Use the above information to estimate the energy difference (kJ/mol) between the gauche and trans states =gt ? 2. (5 pts) If =3001.5J/mol, at what temperature (K) do you expect the equilibrium constant to be equal to 1? 3. (5 pts) What value will the equilibrium constant approach at very low temperature? 4. (5 pts) What value will the equilibrium constant approach at very high temperature