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he rate equation for the second-order reaction of an enzyme (E) and its substrate (S) is V0=KMkcat[E][S] where KMka is the second-order rate constant, which

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he rate equation for the second-order reaction of an enzyme (E) and its substrate (S) is V0=KMkcat[E][S] where KMka is the second-order rate constant, which can be used to compare catalytic efficiencies, Enzymes with a KMkaf near the diffusion-controlled limit are said to have achieved catalytic perfection. What is the diffusion controlled limit in an aqueous solution? 107to109M1s1107to109M1s1109to1010Ms1106to105M109to104M1s1108to109M/s107to108M.S

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