head(Student_data_BUS)

X Record.Number Age Sex Aer Smk Caf Pr Rct Starting_Sal HRs.per.week Major

1 11201121 72 1253872358FIN

2 22181222 80 1504040762FIN

3 33211122 60 1003998855FIN

4 44181222 60 1604016661ACCT

5 55181122 53 1503958058ACCT

6 66181122 81 1403998257ACCT

Run dTest the hypothesis that the true proportion of students who smoke is less than 25%, at the alpha = 0.05 level. What is the p-value you found?

Test the hypothesis that the true average pulse rate is greater than 89. What is the p-value from your test?

Test the hypothesis that the true average hours worked per week is not equal to 55. What is the p-value from your test?

Run a 93%confidence interval for the true proportion of students who don't do aerobics. Which below best matches your interval?

Group of answer choices

[0.58892, 0.72193]

[4.896e-05,0.6585]

[0.58308, 0.72674]

[0.585794, 0.72478]

Run a99%confidence interval for the true proportion of smokers.Which interval below matches what you found?

Group of answer choices

[0.087, 0.235]

[0.098, 0.212]

[0.104, 0.201]

[0.126, 0.169]

Consider a study where we set= 0.01. If we find our p-value to be 0.027, what is our conclusion?

Group of answer choices

Reject the null

Accept the null

Fail to reject the null

Reject the alternative

Consider a study where we set =0.07. If we find our p-value to be 0.0345, what is our conclusion?

Group of answer choices

Reject the null

Accept the null

Fail to reject the null

Reject the alternative

Assume we wanted to show that the true proportion of people who exercise daily is greater than 35%. Let's say we tested at an alpha of 0.10, and found a p-value of 0.03542. Which of the following would be an appropriate conclusionand interpretation?

Group of answer choices

With an alpha of 0.10, and a p-value of 0.03542, we reject the null and state we have sufficient evidence to support that the true proportion of people who exercise daily is greater than 35%.

With analpha of 0.10, and a p-value of 0.03542, we reject the null and state we have sufficient evidence to support that the true average of people who exercise daily is greater than 35%.

With analpha of 0.10, and a p-value of 0.03542, we fail toreject the null and state we have insufficient evidence to support that the true proportion of people who exercise daily is greater than 35%.

With analpha of 0.10, and a p-value of 0.03542, we reject the null and state we have sufficient evidence to support that the true proportion of people who exercise daily is less than 35%.

Which of the following would be a correct interpretation of an 87% confidence interval for the true proportion of students who do aerobics?

Group of answer choices

We are 87% confident that the true proportion of students who do aerobics is between 28.8% and 39.9%.

We are87%confident that the true average of students who do aerobics is between28.8%and39.9%.

We are95%confident that the true proportion of students who do aerobics is between28.8%and39.9%.

We are87%confident that the true proportion of students who do aerobics is between27.3%and41.7%.

Which of the following would be a correct interpretation of a 92% confidence interval for the true proportion of college students who are men?

Group of answer choices

We are 92%confident that the true proportion of college students who are male is between 39.7% and 53.2%.

We are95%confident that the true proportion of collegestudents who are male is between39.9%and54%.

We are92%confident that the proportionof collegestudents who are male is between39.7%and53.2%.

We are8%confident that the true proportion of collegestudents who are male is between46%and46.7%.