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Heat capacity with an empirical equation of Cp=log(0.5T) where Cp(lbmolRBtu) is the heat capacity and T(R) is the temperature. Develop a formula that will enter
Heat capacity with an empirical equation of Cp=log(0.5T) where Cp(lbmolRBtu) is the heat capacity and T(R) is the temperature. Develop a formula that will enter a temperature in terms of Kelvin (K) and solve Cp(gmolKJ)Cp=0.2388log(1.11T)Cp=log(1.11T) None of the choices Cp=4.1868log(0.9T)Cp=log(0.9T)
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