Hector read that the traditional drink in Tibet is tea with added butter. Inspired by this idea, he decides to investigate how a thin layer of fat on the top of a hot liquid affects the cooling of the liquid. He performs two different experiments. Experiment 1: Hector pours 100 m1 of boiling water into each of two Styrofoam cups and adds a thin (2.0-mm) layer of hot oil (at about 100C ) to one of the cups. He measures the initial temperature in the cups, waits for 10 minutes, and then measures the temperature again. His measurements are shown below. Cup A Cup B (no oil) (with layer of oil) Ti 99C 99C Tf 84C 95C Experiment 2: Hector puts two empty Styrofoam cups on separate precision scales and zeroes the scales. Then he pours 100 ml of boiling water into each cup and adds a 2.0-mm layer of hot oil to one of the cups. He records the initial readings of the scales, waits for 10 minutes, and then records the readings of the scales again. His data are shown below. Cup A Cup B (no oil) (with layer of oil) mi 99.00 g 104.00 g m 97.00 g 104.00 g V Part A Why does hot water with a layer of hot oil cool more slowly than water without oil? Select the correct explanation. Oil has a much higher specific heat capacity than water, and the water combined with the oil layer cools more slowly than the water without oil. The oil layer prevents the water from evaporating, which decreases the rate of change of internal energy of the water. The oil layer prevents the water from evaporating, which increases the rate of change of internal energy of the water. Oil has a much lower specific heat capacity than water, and the water combined with the oil layer cools more slowly than the water without oil. Previous Answers V Correct Part B Determine the change in thermal energy of water due to evaporation in experiment 1. Express your answer with the appropriate units. AUevap = -4600 J Part C Does the value AUevap correspond to the loss of water mass in experiment 2 without oil, if the heat of vaporization for water is about 2.4 x 106J/kg? The value AUevap does not correspond to the loss of water mass. The value AUevap corresponds to the loss of water mass. Part D If Hector used room-temperature oil instead of oil at 100C, what would the nal temperature of the water in experiment 1 with oil be? The temperature would be equal to 95C. The temperature would be less than 950 C. The temperature would be higher than 950 C. Part E If Hector used room-temperature oil instead of oil at 100 C, what would the final mass of the water in experiment 2 with oil be? The mass would be less than 104.00 g. The mass would be greater than 104.00 g. The mass would be equal to 104.00 g. Previous Answers V correct Part G Determine the density of water at 100 C. Express your answer with the appropriate units. mgsao.? k water = 20_0 g m3 Submit Previous Answers R_equest Answer 3' Incorrect; Try Again; 5 attempts remaining Part H Determine the density of oil at 100C. Express your answer with the appropriate units. $5600.? pou= Value | Units