Helium gas with a volume of 3.20 L, under a pressure of 0.160 atm and at a temperature of 45.0. C, is warmed until both pressure and volume are doubled. Note that 1L = 0.001m, latm = 1.013 - 10 Pa , and temperature in Kelvin is related to the temperature in degrees Celsius as follow: T(Kelvin) - T(Celsius) + 273. What is the final temperature? Express your answer in degrees Celsius. Report the result with three significant figures. AEQ DO ? T =