hello, can you explain the process of these answers? like how did it get to that answer. it is already answered but the problem is i don't know how to solve these and how did it happened.

explain in a very detailed way that a slow leaner would understand. (in a sentence)

like a tutor/teacher explaining it to his or her students how to solve a problem. explain everything. thank you so much!

example: "the given of this problem is 10. To get the formula we will use the___. Then cancel out this one. and for the solution we will substitute the___ "

1 and 2

Problem Solving with Resistance 1 . ) what is the resistivity of a material with 2 . ) An electrical engineer wants to have a vesistance of 10 1, length of 10 m and a copper wire with resistance equal to cross sectional arca of 1x 10-4 2? SA . If the wire initially has a radius of 1 mmm , how long should the engineer . Given : out the wive? R = lon 1 = 10 m . Given : A = 1 x1062 Pcopper = 1. 72 * 10 nom P = ? R = 50 1 = Imm = 1X10 m . Formvila 1 = ? R PI A =?. T A PY = RA . Formula : . Solution : Y 1 A = Try A = TT ( ( x 10 3 m) " RA R - PI = TT (1 X 10 -4 M 2) P P = A= TT x 106 m 2 RI RA 4- ( 5m) ( TT x 10 - 6 m? ). . solution: P 1. 72 x 10 8 2 - m P . ( 10 2 ) ( 1 x 10 6 m 2) 1 = RA | 1 . 5 708 x 10ish . m2 10 m P 1 . 72 x 10 0_- m 1 xlon. m 2 1 = 913. 26 m . / 10 m P = 1xlon.m/ There fore, the engineer should out the wire 913. 26 m long . Therefore, the material's resistivity is 1 x10 n .m