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Hello I am working on part B of this question. The example shows how z score of 15.15 equals cumulative area of 1.0000 Could you

Hello

I am working on part B of this question.

The example shows how z score of 15.15 equals cumulative area of 1.0000

Could you explain how they got there?

My positive z score sheet goes up to 3.50, and the online z score calculators online take value from -6 to 6, and will not take value of 15.15

In my question, I got an answer of 17.86 for the z score (17.85714286 rounded up)

x= 74 u=69.0 o= 2.8 n=100

image text in transcribedimage text in transcribed
6.4. 19- Assigned Media An airliner carries 200 passengers and has doors with a height of 74 in. Heights of men are normally distributed with a mean of 69.0 in i View an Example X a. If a male passenger is randomly selected, find the probability that he can fit through the doorway without bending. Question Help The probability is .9633 . (Round to four decimal places as needed.) An airliner carries 100 passengers and has doors with a height of 75 in. Heights of men are normally distributed with a mean of 69.0 in and a standard deviation of 2.8 in. Complete parts (a) through (d). b. If half of the 200 passengers are men, find the probability that the mean height of the 100 men is less than 74 in. The probability is the population mean, o is the population standard deviation, and n is the sample size. (Round to four decimal places as needed.) x - H Z= Substitute x = 75, u = 69.0, o = 2.8, and n = 50 into the formula and simplify, rounding to two decimal places. 75 - 69.0 Z = 2.8 Substitute. 150 = 15.15 Simplify. Now use technology to find the cumulative area under the standard normal curve to the left of z = 15.15, rounding to four decim The cumulative area is 1.0000. Press Continue to see more. ? Enter your answer in the answer box and then click Check Answer. 4 parts Continue Close remainingb. If half of the 100 passengers are men, nd the probability that the mean height of the 50 men is less than 75 in. Since the original population has a normal distribution, the sample means also have a normal distribution, with mean p and standard deviation 0 l W . First convert the sample mean i = 75 to the oorresponding z score using the formula shown below, where |.1 is the population mean, 0 is the population standard deviation, and n is the sample size. 2: U n

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