Hello, I have having a difficult time answering number eight. And if you have the time could you perhaps check if my other work is correct? It'd be super useful, thanks for any help!
8/11/2020 Apex Learning - Test 4.10.4 Test (TST): Three-Dimensional Solids Test Geometry Sem 2 Name: Rayanne Fadich Points Possible: 50 Date: Answer the following questions using what you've learned from this unit. Write your responses in the space provided. 1. You are making a fruit salad. You cut a banana in half and think of it as a cylinder with the cut you made as its base. Then, you consider the different shapes you can get depending on the way you cut the banana. Part 1: Describe the shape of the cross sections if you slice the banana parallel to its base. Draw a picture of the shape. (1 point) The shape of the cross section would be a circle. Part II: Describe the shape of your cross sections if you slice the banana at a 45 . angle to its base. Draw a picture of the shape. (1 point) The shape of the cross sections would be an oval Part III: Describe the shape of your cross sections if you slice the banana in half, with a cut perpendicular to its base. Draw a picture of the shape. (Hint: Remember to think of the banana as ://course.apexlearning.com/public/cpop/4/10/4/1461932 1/78/11/2020 Apex Learning - Test a cylinder.) (1 point) 2. The surface area of a three-dimensional figure is the sum of the area measures for each of the figure's faces. Find the surface area of the cube shown below. 3 in. 3 in. Part 1: How many faces does the cube shown above have? (1 point) The cube has 6 faces. Part II: Find the area of one face of the cube shown above. Show your work. (2 points) A= bh = 3.3 = 19in Part III: Find the surface area of the cube shown above. Show your work. (2 points) SA = 602 = 6(3) 2 = 6.9 = /54 in 3. Find the surface area of the cylinder shown below. The surface area of a cylinder can be found by: SA = 2xth + 2xr? /course.apexlearning.com/public/cpop/4/10/4/1461932 2/78/11/2020 Apex Learning - Test 5.cm 8 cm Part 1: Find the lateral area of the cylinder by using the 27/h portion of the formula above. Show your work and leave your answer in terms of pi. (2 points) A= 2Tirh = 2TT(5) (8) = 251.33 cm Part II: Find the area of the bases of the cylinder by using the 277 2 portion of the formula above. Show your work and leave your answer in terms of pi. (2 points) A = 2 TTrz = 2 TT ( 5 ) 157.07: 2= 78.54 cm = 2TT25 = 157.07 cm Part Ill: Use your answers from Parts I and Il to find the surface area of the cylinder above. Show your work and round your answer to the nearest tenth. (1 point) 78.54 . 2 = 157.07+ 157.07+ 251.33= 408.4cm 4. Suppose you have a funnel in the shape of a right cone as shown below. Find the lateral area. 15 cm -16 cm Part I: Find the radius of the cone. (2 points) 16:8= 18 cm) Part II: Use your answer from Part I with the Pythagorean Theorem to find the slant height of the cone. Show your work. (3 points) Arth2 = 289 16# 2=8 J 82+152 17 cm course. apexlearning.com/public/cpop/4/10/4/1461932 = J64+ 225 3/78/11/2020 Apex Learning - Test Part Ill: Use the formula below to find the lateral area of the cone pictured above. Show your work and round your answer to the nearest hundredth. (5 points) 16:2=8 LA=TirS Lateral area of a =TT(8)(17) cone: = 427.30cm LA = TIS 5. Part 1: Find the volume of the cylinder shown using the formula in the box below. Round your answer to the nearest tenth. Show your work. (5 points) V= Tirh The volume of a cylinder: 1= TT ( 7.4) ( 11.4) = TT (54. 76) ( 11.4 ) V = $12 h 1 1, 961.20 cm 11.4 cm 17.4 cm ourse.apexlearning.com/public/cpop/4/10/4/1461932 4/78/11/2020 Apex Learning - Test 6 Part 1: Suppose a prism has a square base with each side of length 3.75 cm and a height of 5.65 cm. Use the formula below to find the volume. Show your work and round your answer to the nearest hundredth. (5 points) V= Bh The volume of a = (14.06) (5.65) 5.65 am prism: = 79.50 cm V = Bh Base = bh 3.75 cm B= 14. 06 3.75 cm 7. Suppose a sphere has a volume of 3,000 cm3. Find the surface area. The volume of a sphere: V = ry 3 Part I: Find the radius of the sphere by setting the volume equal to the formula above. Show your work and round the radius to the nearest hundredth. (5 points) 6 3,009 3 r = (3 4 TT 3,000 = = TTr 3 = (3.2, 356) 3 3:000 = 4. 19 r3 4.19 4.19 = (7,068) 3 715. 9 = 13 = 8.95 r =/8.95 rse.apexlearning.com/public/cpop/4/10/4/14619328/11/2020 Apex Learning - Test Part II: Use the radius you found in Part I with the surface area formula below to the find the surface area of the sphere. Show your work and round your answer to the nearest tenth. (5 points) The surface area of a SA = 4 TTrz sphere: = 4 TT ( 8. 95 ) 2 SA = 4xr? = 4TT(80.10) = 1,006 cm 8. The volumes of two similar solids are 512 cm3 and 2,197 cm3. If the smaller solid has a surface area of 960 cm2, find the surface area of the larger solid. Part I: Find the similarity ratio by taking the cube root of each volume. Show your work. (2 points) J512 = 8 J 2 197 = 13 38/11/2020 Apex Learning - Test Part II: Use your answer from Part I to find the ratio of the surface areas. Show your work. (2 points) Part III: Set up a proportion and solve to find the surface area of the larger solid. (3 points) ht @ 2018 Apex Learning Inc. Use of this material is subject to Apex Learning's Terms of Use. Any unauthorized copying, reuse, or redistribution ited. Apex Learning @ and the Apex Learning Logo are registered trademarks of Apex Learning Inc
