Hello, I sincerely hope that you can help me with this question. It makes no sense to me. Thank you!

The question:

Confidence Intervals for the Mean sigma known

Assuming .05 as your alpha value, make up a problem similar to this one. Make up 36 gas prices for your example. Use price values in your list that some you made up and be sure they are similar to the prices you have had in your area.List the values in your post.

Instructions for your response.

In your response, copy the original problem, describe what you did and give the mean, standard deviation and confidence interval. Then attach the excel spreadsheet.

Example below:

• First find the mean. List all 36 gas prices in cells A1 to A36 in your excel spreadsheet.
• On a different cell type in =average(A1:A36) and the hit enter to find the average
• Assume your answer is 2.65
• On a different cell type in=stdev.s(A1:A36)or =stdevA(A1:A36) and enter to find the standard deviation
• Assume your answer is .43
• Then type this in an excel cell=confidence.norm(.05,.43,36)and hit enter. This is the E value
• So take the mean of 2.65 and you have (2.65-E, 2.65+E) for your confidence interval

Formula you used above for the confidence interval:

The formula is E= zsubc * sigma / sqrt n

Where the left hand endpoint is xbar - E and the right hand endpoint is xbar + E

Just a review of your instructions:

First you will make up a problem with alpha = .05 and give the values for the problem.