Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Hello, I'm having trouble understanding the strategy for solving this problem.I know the answer is that it converges by the Alternating Series Test. I realize

image text in transcribed

Hello, I'm having trouble understanding the strategy for solving this problem.I know the answer is that it converges by the Alternating Series Test. I realize that for this to happen, two things must be true: (1.) The limit of "a sub n" must equal 0, and (2.) "a sub (n+1)" must be less than or equal to "a sub n". I found the limit to be equal to 0 but I don't know how to find whether "a sub (n+1)" is less than or equal to "a sub n".Could someone please explain the steps to this?

image text in transcribed
Determine whether the alternating series > (- 1)n+1 Vn + 1 converges or diverges. n + 3 n = 1 . . . Choose the correct answer below and, if necessary, fill in the answer box to complete your choice. O A. The series does not satisfy the conditions of the Alternating Series Test but converges because it is a p-series with p = O B. The series does not satisfy the conditions of the Alternating Series Test but diverges by the Root Test because the limit used does not exist. O C. The series does not satisfy the conditions of the Alternating Series Test but diverges because it is a p-series with p = O D. The series does not satisfy the conditions of the Alternating Series Test but converges because it is a geometric series with r= O E. The series converges by the Alternating Series Test

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access with AI-Powered Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Income Tax Fundamentals 2013

Authors: Gerald E. Whittenburg, Martha Altus Buller, Steven L Gill

31st Edition

1111972516, 978-1285586618, 1285586611, 978-1285613109, 978-1111972516

Students also viewed these Mathematics questions