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. Question 1 . Question 1 The image shown depicts a right triangle that is p right triangle that is perpendicular to a rectangle. You may wish to think of the rectangle as lying on a table top and the triangle protruding from the table. One leg of the triangle (AC ) In In- Class Activity 6.D, you learned that a triangle's missing leg can be found more quickly by using cose - adjacent Content Activities v Tools v Grades v Help v able of Contents > Unit 2: Right Triangle Definitions, Solving Equations, Inverse Sine & Cosine, Sine & Cosine Identities RF2_7B_Preview cos(8).sin(0)) x2 + y2 = 1 RF2_7B_Preview Score : 0/7 0/3 answered . Question 1 Average rate of change If the two points ' (x_1.y_1) and "(x_2.y_2)" are on the graph of y=f(x), then the average rate of change of f between these two points is given by the formula : If AB = 7. BC = 5, and CD = 6. find the length of hypotenuse AD. art A: Determine the length of the second leg of the right tr Average rate of change "=(Delta y)/(Delta x)=(y_2-y_1)/(x_2-X_1)"* The symbol 'Delta" the Greek letter delta. Hint You will need to determine AC first. Label what you know on the diagram. Example: Compute (Delta y)/(Delta x)"between the points "(-2,1)' and "(3, 4). Answer: *)=(y_2-y_1)/(x 2-x_1)=1-4-1)/13-(-21=1-5y's =4. Plugging into the formula, we get (Delta y)/(Delta 25 in Question Help: Message Instructor Try It RF2_6D_Preview 0 = 49" Compute '(Delta y)/(Delta x)" between the points (1,-1) and "(-5,4) . (Delta y)/(Delta x)=[ RF2_6D_Preview uestion Help: Message instructor Calculator Score: 0/2 0/3 answered Submit Question . Question 2 f 48 - 7.BC - 3, and AD - 9, find the length of CD. Hint Answer: Question Help: Message instructor Calculator Submit Question the nearest tenth. RF2_7B_Preview Score: 0/7 013 . Question 2 Assume that the points (1,2) and " (3,3) are on the graph of a function f. Part A: Compute (Delta yy(Delta x) between these two points. Hint 10 m Delta yy(Delta x)= Tents , Unit 2 Right Triangle Definitions , S tons. Inverse sie & Cosine, Sine & Cosine Ident F2_6D_Practice ~ Part B: Instead of computing (Delta y). RF2_6D_Practice Hint Score: 0/4 0/2 answered Question 2 nearest determine the length ofthe (Delta xy/(Deltay boat is anchored, but there is a strong current. so the fishing line enters the water at an angle (see the fisherman's weight on the ocean with the Part C: Suppose Jenna is computing Delta y and Delta x b xy/(Delta y) in the following cases, and Boat /25. "(Delta y)/(Delta x) (Delta x)/(Delta y) 29 . 2 m Delta x-5' Delta x=10' "Delta x = 25' Ocean Floor " Delta x=50' yes Part D: Which of the following statements are true ? ( There may be more than one right answer. Dif (Delta y)/(Delta x) gets smaller and smaller, then (Delta x/(Delta y) gets larger and larger if (Delta y)/(Delta x) gets smaller and smaller. then (Delta x)(Delta y) will also get smaller If (Delta y)/(Delta x) gets larger and larger. then (Delta XM(Delta y) gets sma (Delta xy/(Delta y) is the reciprocal of " (Delta y)/(Delta x); PhotoGrid