help me please

Assume that 10% of people are left-handed, If 5 people are selected at random, find the probability of each outcome described below. a) Find the probability that the first lefty is the third person chosen. 0/031 (Round to four decimal places as needed.) b) Find the probability that there are some lefties among the 5 people. 0.4095 (Round to four decimal places as needed.) c) Find the probability that the first lefty is the fourth of fifth person. 0.1385 (Round to four decimal places as needed.) d) Find the probability that there are exactly 3 lefties in the group. (Round to four decimal places as needed.) e) Find the probability that there are at least 3 lefties in the group. (Round to four decimal places as needed.) ") Find the probability that there are no more than 2 lefties in the group, [(Round to four decimal places as needed.)