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Use the t-distribution to find a confidence interval for a mean given the relevant sample results. Give the best point estimate for the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed. A 99% confidence interval for using the sample results T = 95.7.5 = 31.7, and n = Round your answer for the point estimate to one decimal place, and your answers for the margin of error and the confidence interval to two decimal places point estimate-057 margin of error 5.93 The 99% conndence interval is 89.77 to 1 101.43