help!! using pandas/python will def upvote if its correct

both 2a and 2b

\# filter 1995 names names_95 = baby_names[baby_names.Year == 1995] How many individuals were counted in total in 1995 ? We can address that by computing a sum of the counts: # n for 1995 names_95.Count.sum() =494580 What is the typical frequency of all names in 1995 ? We can address that by computing the average count: \# average count for a name in 1995 names_95.Count.mean() :81.18516086671043 Question 2a Compute the maximum count of names given in 1995 and store this as names_95_max_count. Use this value to filter names_95 and find which name is the most frequent in that year. Store the filtered dataframe as names_95_most_common_name . names_95_max_count = names_95.Name.sum() names_95_most_common_name = names_95_max_count. Count.sum() print("Number of people with the most frequent name in 1995 is :", names_95_max_count, "people") print("Most frequent name in 1995 is:", names_95_most_common_name.values[0]) AttributeError Traceback (most recent call last) in 1 names_95_max_count = names_95. Name. sum ( ) 2 names_95_most_common_name = names_95_max_count.Count.sum() 3 5 AttributeError: 'str' object has no attribute 'Count' ]: \# number of individuals by sex names_95_bysex.Count.sum( ) The most frequent boy and girl names can be found using .idxmax ( ) groupwise to obtain the index of the first occurence of the maximum count for each sex, and then slicing with . loc : ]: \# first most common names by sex names_95. loc[names_95_bysex.Count.idxmax ( ), : ] Since . idxmax () gives the index of the first occurrence, these are the alphabetically first most common names; there could be ties. You know from Q2a that there are no ties for the male names; another filtering step can be used to check for ties among the female names. ]: \# ties? names_95[names_95_bysex.Count. max(), values [ 0]== names_95 ['Count'] ] So, no ties. Question 2b Are there more girl names or boy names in 1995? Use the grouped dataframe names_95_bysex with the . count ( ) aggregation to find the total number of names for each sex. Store the female and male counts as girl_name_count and boy_name_count , respectfully