Hi, Good evening or good morning, relative to your time, my dear teacher, can I know the following answers and how to extract them from the picture? Thank you

Con: Computer Organization

AX 4000 BX 0123 CX CO2D DX 0000 Cpu speed: 3000 cycles, Frameskip 0, Program: AFD SI 0000 CS 19F5 IP 011F Stack +0 0000 Flags 7204 DI 0000 DS 1975 +2 20CD BP 012B ES 1975 HS 19F5 +4 9FFF OF DF IF SF ZF AF PF CF SP FFFE SS 19F5 FS 1975 +6 EADO 0 0 1 0 0 0 1 0 CMD > 010B 83C302 010E 83C502 0111 8B07 0113 894600 0116 8B4702 0119 894602 011C B80040 011F CD21 0121 64 ADD ADD MOV MOV MOV MOV MOV INT DB BX,062 BP,0002 AX,[BX] [BP+00],AX AX,[BX+02] [BP+021, AX AX, 4000 21 1 0 1 2 3 4 5 6 7 DS:0100 BB 21 01 BD 27 01 8B 07 DS:0108 89 46 00 83 C3 O2 83 C5 DS:0110 02 8B 07 89 46 00 8B 47 DS: 0118 02 89 46 O2 B8 00 4C CD DS: 0120 21 64 00 08 00 2C 01 64 DS:0128 00 00 00 08 00 2C 01 7E DS:0130 8C E8 78 BD DE F9 36 2A DS:0138 66 2C 1E DC D4 1F D7 32 DS: 0140 8D A8 3A 6A 48 94 DA 1C DS:0148 79 74 99 ZA ED 06 51 F2 64 2 2 DS:0100 DS:0110 DS:0120 DS:0130 DS:0140 0 1 2 3 4 5 6 7 BB 21 01 BD 27 01 8B 07 OZ 8B 07 89 46 00 8B 47 21 64 00 08 00 2C 01 64 8C E8 78 BD DE F9 36 2A 8D A8 3A 6A 48 94 DA 1C 8 9 A B C D E F 89 46 00 83 C3 02 83 C5 O2 89 46 O2 B8 00 4C CD 00 00 00 08 00 2C 01 7E 66 2C 1E DC D4 1F D7 32 79 74 99 ZA ED 06 51 F2 2.1.2 1.1.. F.ah.at ..ef.it .eF. ta...d L. iox|6* f,...#2 i:jhor. ytong.Q2 Step 2ProcStep 3Retrieve 4 Help ON SBRK Menu 6 7 up 8 dn 9 le 10 ri Fig Part I: For the Debugger interface shown in Fig 1, answer the following questions: What are the contents of register BL (in hex format)? What are the contents of register BP (in hex format)? Ans: Ans: What is the byte stored at memory address 012B (hex format)? What is the word stored at memory address 012D (hex format)? Ans: Ans: What is unsigned decimal number stored in the byte at memory address 012B? What is unsigned decimal number stored in the word at memory address 012D? Ans: Ans: What is the length of the instruction ADD BX, 0002 in bytes? What is the machine code for instruction MOV AX, [BX] ? Ans: Ans: AX 4000 BX 0123 CX CO2D DX 0000 Cpu speed: 3000 cycles, Frameskip 0, Program: AFD SI 0000 CS 19F5 IP 011F Stack +0 0000 Flags 7204 DI 0000 DS 1975 +2 20CD BP 012B ES 1975 HS 19F5 +4 9FFF OF DF IF SF ZF AF PF CF SP FFFE SS 19F5 FS 1975 +6 EADO 0 0 1 0 0 0 1 0 CMD > 010B 83C302 010E 83C502 0111 8B07 0113 894600 0116 8B4702 0119 894602 011C B80040 011F CD21 0121 64 ADD ADD MOV MOV MOV MOV MOV INT DB BX,062 BP,0002 AX,[BX] [BP+00],AX AX,[BX+02] [BP+021, AX AX, 4000 21 1 0 1 2 3 4 5 6 7 DS:0100 BB 21 01 BD 27 01 8B 07 DS:0108 89 46 00 83 C3 O2 83 C5 DS:0110 02 8B 07 89 46 00 8B 47 DS: 0118 02 89 46 O2 B8 00 4C CD DS: 0120 21 64 00 08 00 2C 01 64 DS:0128 00 00 00 08 00 2C 01 7E DS:0130 8C E8 78 BD DE F9 36 2A DS:0138 66 2C 1E DC D4 1F D7 32 DS: 0140 8D A8 3A 6A 48 94 DA 1C DS:0148 79 74 99 ZA ED 06 51 F2 64 2 2 DS:0100 DS:0110 DS:0120 DS:0130 DS:0140 0 1 2 3 4 5 6 7 BB 21 01 BD 27 01 8B 07 OZ 8B 07 89 46 00 8B 47 21 64 00 08 00 2C 01 64 8C E8 78 BD DE F9 36 2A 8D A8 3A 6A 48 94 DA 1C 8 9 A B C D E F 89 46 00 83 C3 02 83 C5 O2 89 46 O2 B8 00 4C CD 00 00 00 08 00 2C 01 7E 66 2C 1E DC D4 1F D7 32 79 74 99 ZA ED 06 51 F2 2.1.2 1.1.. F.ah.at ..ef.it .eF. ta...d L. iox|6* f,...#2 i:jhor. ytong.Q2 Step 2ProcStep 3Retrieve 4 Help ON SBRK Menu 6 7 up 8 dn 9 le 10 ri Fig Part I: For the Debugger interface shown in Fig 1, answer the following questions: What are the contents of register BL (in hex format)? What are the contents of register BP (in hex format)? Ans: Ans: What is the byte stored at memory address 012B (hex format)? What is the word stored at memory address 012D (hex format)? Ans: Ans: What is unsigned decimal number stored in the byte at memory address 012B? What is unsigned decimal number stored in the word at memory address 012D? Ans: Ans: What is the length of the instruction ADD BX, 0002 in bytes? What is the machine code for instruction MOV AX, [BX] ? Ans: Ans