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Hi:) I have a couple of questions regarding the interval value theorem. Using the intermediate value theorem, show that the polynomial f(x) = x^3 -
Hi:) I have a couple of questions regarding the interval value theorem.
- Using the intermediate value theorem, show that the polynomial f(x) = x^3 - 15x + 1 has three zeros on the interval [-4,4]. (consider the values of f(x) at x = 4,3,1,0,-1,-3,-4)
- Verify that the intermediate value theorem applies on the indicated interval of [0,3] when given f(x)=x^2 - 6x +8, and find the value of c such that f(c)=11.
- Take the values in the table listed below of two continuous functions g(x0 and f(x):
x | -5 | -2 | 1 | 2 | 4 |
f(x) | 4 | 8 | -2 | -5 | -7 |
g(x) | -1 | 7 | -4 | -3 | 3 |
Which interval is guaranteed to contain a point c such that g(c)=f(c) and why?
A) (2,4)
B) (-5,-2)
C) (-2,1)
D) (1,2)
Thank you!
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