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Hi I need help on the following question: The solution of a certain differential equation is of the formy(t)=acos(3t) + bsin(3t) , wherea andb are
Hi I need help on the following question:
The solution of a certain differential equation is of the formy(t)=acos(3t) + bsin(3t) , wherea andb are constants.
The solution has initial conditions y(0) = 1 and y'(0) = 4
Find the solution by using the initial conditions to get linear equations foraandb
so what did is set y(0) = 1 in the equation and I got a = 1.
I'm having a hard time with getting y'(0)=4
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