Hi,

im looking for a step by step of what is happening here. no instructions or explanations were provided with this calculation and i have no idea what i am looking at.

thank you so much in advanced!!

Learning activity 1.4: Using first principles to determine the equation of a tangent Derivative = f' (x ) = y' = lim f(xth)-f(x) h - 0 Example: Find the derivative of f (x ) = 2x - x2 using first principles. Given the x value, a, m = lim f(ath)-f(a) h-0 f' ( x = lim f (xth)-f(x) h-0 f' ( x = lim [2(xth)-(xth)?]-[2x-x2] h-0 fix = lim [2x+2h-x2-2xh-h=]-[2x-x3] huh h X = lim - 2x+2h-x2-2xh-h2-2x+x2 h-0 h f' ( x = lim 2h-2xh-h2 h f' ( x = lim h(2-2x-h) h-0 fix = lim ( 2 - 2x - h ) h-0 f' x ) = 2 -2x - 0 f' x =2 - 2x