Hi teacher i hope you can help me out here

You should use algebra in all parts of this question, showing your working clearly. (a) Solve the following equations, giving your answers as integers, fractions or surds in their simplest form. (i) 16x+3= -4x - 7 (ii) 10 + (4 -2x) = x +6 (iii) x - 3 (b) Solve the equation 2x2 + 38x + 140 =0 by factorisation. (c) A student was asked to rearrange the formula Sa + 6b = 26 - 3c 3b - 5 to make b the subject. The student's incorrect attempt is shown below. The equation is: - Za + 60 = 26- 30 36 5) Multiply both sides by 3: - a + 180 = 60 - 90( 30 -5) Multiply out brackets: -a + 186 = 66- 2709- 450 2 Multiply both sides by 2: -20 + 360 = 126 - 2760- 900 collect b terms on one side: 246 - 27bc = 20 - 90c Factorise Left-hand side: 6 (24 - 270) = 20 - 900 Divide both sides by 24 - 270 to give: b = 20 - 90c 24 - 270 (i) Write out a correct rearrangement of the formula. (ii) Identify and explain, as if directly to the student, two of the three mistakes made by the student