Hi there,

I have the bellow question:

With the bellow answer:

Can anyone please explain what makes an expression turn TRUE or FALSE based on the operators given? How do these operators work?

Thank you

(C) main(). c { int i = 4, j = -1, k = 0, W, X, Y, Z; w = i || j || k; x = i && j && k; y = i | j && k; z = 1 &&j || k; printf (" w = %d x = %d y = %d z = %d", w, x, y, z); } = B. 1, 1, 0, 1 D. 1,0, 1,1 A. 1, 1, 1, 1 C. 1, 0, 0,1 Answer & Explanation Answer: Option D Explanation: Step 1: int i=4, j=-1, k=0, W, X, Y, z; here variable i, j, k, W, X, Y, Z are declared as an integer type and the variable i, j, k are initialized to 4,-1, 0 respectively. Step 2: w = i || j || k; becomes w = 4 || -1 || 0;. Hence it returns TRUE. So, w=1 w = Step 3: x = i && j && k; becomes x = 4 && -1 && 0; Hence it returns FALSE. So, x=0 = Step 4: y = i ll j &&k; becomes y = 4 || -1 && 0; Hence it returns TRUE. So, y=1 Step 5: z = i && j || k; becomes z = 4 && -1 || 0; Hence it returns TRUE. So, z=1. Step 6: printf("%d, %d, %d, %d ", w, x, y, z); Hence the output is "1, 0, 1, 1