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Pl3ase answ3r the following in g00gle docs in a typ3written format and just shar3 me the link after or in a neatly handwritt3n format in a plain white paper -- ALL INSTRUCTIONS/REFERENCES are provided in the picture

I will rate the tutor HELPFUL (thumbs up) if answered ASAP in g00gle docs in a typ3written format and just shar3 me the link after or in a neatly handwritt3n format in a plain white paper

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A. Answer the following question in complete sentences. 1. What is capacitance? B. Solve the given problem. Show your complete solution. 1. The parallel plates of an air capacitor are separated by 2.25 mm. Each plate carries a charge of 6.50 nC. The magnitude of the electric field of the plates is . Find the (a) potential difference between the plates, (b) capacitance, and (c) are of a plate.In a charged parallel-plate capacitor, the stored charges +Q in the plates give rise to an electric field E between the plates. (Refer to the figure at the right-electric field in a charged parallel-plate capacitor) To gain insight into how this energy may be expressed (in terms of Q and V), consider a charged, empty, parallel-plate capacitor; that is, a capacitor without a dielectric but with a vacuum between its plates. The space between its plates has a volume Ad. and it is filled with a uniform electrostatic field E. The total energy U. of the capacitor is contained within this space. The energy density U. in this space is simply U. divided by the volume Ad. If the energy density is known, the energy can be found as U. = U. (Ad). In Electromagnetic Waves (after completing the study of Maxwell's equations), the energy density U, in a region of free space occupied by an electrical field E depends only on the magnitude of the fit u = en 12. Multiplying the energy density by the volume between the plates, the amount of energy stored between the plates of a parallel-plate capacitor Uc = up(Ad) = beof Ad = tents Ad = \\Ve4 = \\Vac In this derivation, we used the fact that the electrical field between the plates is uniform so that and .Because we can express this result in other equivalent forms: QV