Question
Homegrown strncpy implementation C programming Objectives Practice imlpementing an algorithm Practice working with strings in C In this lab, you are going to create your
Objectives
Practice imlpementing an algorithm
Practice working with strings in C
In this lab, you are going to create your own implementation of thestrncpyfunction from the C Library. Recall that the strncpy copies a given number of character elements from a source character array (string) into a destination character array. You will write a functionmy_strncpythat replicates the behavior of the built-in strncpy function. Your main method will test this function out with different source and destination arrays. Remember that a character array can be represented as a character pointer to the first element, as is done in the prototype for strncpy and our own my_strncpy function. NOTE: don't use any functions from string.h in this lab. Requirements: Your my_strncpy function will have the following prototype:char *my_strncpy(char *dest, char *source, int n)
Notice that the function returns a pointer to a char. Like the built-in function, you will simply returndest.
You will use a loop to assign the firstnelements ofdestto the first n elements ofsource.
HINT:Even thoughsourceanddestare passed in as pointers and not arrays, you can still use the subscript [ i ] notation to access the ith element.
You could also use pointer arithmetic to increment source and dest to point to their next element on each iteration.
Remember that the null character \0 must be appended todestat indexn
Your function does not need to do any safety checks to make sure n is less than the length of dest.
Test your function by inserting your my_strncpy function into the appropriate place in the following program.
/*
* Homegrown strncpy test program
*/
#include
// Function prototypes
char *my_strncpy(char *dest, char *source, int n);
// ********* Insert your my_strncpy implementation here! *************
int main() {
// Test your function with various source strings and values of n
char testSrc[] = "Hello";
char testDest[40];
int n = 5;
my_strncpy(testDest, testSrc, n);
printf("%s ", testDest);
return 0;
}
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