How could the values be manipulated in order to yield a smaller % difference

Goal: You will learn when and how to apply the separate principles of energy and momentum conservation to solve a dynamical problem. 1. Obtain a projectile launcher and shoot the ball horizontally onto the floor. By taking appropriate measurements (e.g., the initial height of the ball, the range of the projectile) calculate the speed vo with which the ball exits the launcher. . 92 h = 85 cm Vi = Q 2h 2 (.85 ) = 5.4 m/s? 9.8 d = 92 cm 2. The ball, which has mass m, collides with and sticks to an initially stationary pendulum of mass M. This is a fully inelastic collision. After the collision the pendulum-ball combination rises by some height h. pivot7 m = 6 6g M = 240g M a) Use an appropriate conservation law valid from the instant just before m V impact until just after the collision ends to calculate the velocity v1 of the pendulum-ball combination immediately post-collision. 9 = 35" - ( m + M ) v 2 = ( m + M )gh V 1 = m m + M ) Vo VI = ( 0.066 kg ) ( 0.24 ky + 0.061 ) ( 5. 4 m/s ) = 1.1647 m/s b) Use an appropriate conservation law valid from just after the collision ends until the pendulum stops rising to calculate h. 2 ( m + M ) v ' 2 6.066 + 0.240 ) ( 1 164 ) 2 h = = 0.0692. ( m + M)g ( .06 6 + 0 . 240 ) ( 9 .8 ) h ( theory) = 0.0692 m 3. a) Fire the ballistic pendulum apparatus to obtain h experimentally. Measure the angle of swing using the scale near the pivot and the black plastic needle. You will need to use trigonometry to relate the change in height h to the angle. The length of the pendulum from the pivot to its center of mass is L = 30 cm. 0 = 50- 15= 35" h= e - (R cos ( 35 ) ) L = 0.3 m h = 0. 3 m - 10.3 m Cos ( 35 ) h = 0 0543 m h (expt ) = 0. 0543 m b) What is the percent difference of your theoretical h from your experimental h? %% difference = experimental -theoretical 0. 0543 - 0.0692 theoretical 0.0692 %% difference = 21.5%