How could their mass spectra be used to distinguish between the following compounds? Check all that apply. 2. Heptinone will have a base peak at m/z=99. whereas the other two ketonos wal have base peaks at m/2=43. 2. 4.Dimethyl3. pertanone will have a base pe ak at m/z=57, whereas the obier tro ketones will have base peaks at m/7=43. 2-Heptanone has yhydrogens. Therefore. It cannot undergo a Mctafferty rearrangement so it will not have a peak at m/==58 or at m/=86 2.4.Dimetyyl-3-pontanone does not have any yhydrogens. Therefore. It cannot undergo a Mcl.afferty rearrangement, so it will not have a peak at m/=58 24. Dimethyl-3-pentanone wili have a peak at m/z=58 due to a Mctallertv rearrangement. Check all that apply. 2H Heptanone will have a base peak at m/z=99. wheseas the other wo ketones will have base peaks at m/z=43 24-Dimethl-3-pentanone will have a base peak at m/z=57, whereas the other two ketones will have base peaks at m/z =43 2. Heptanone has phydrogens. Therefore, it cannot undergo a McLafferty rearrangement so it will not have a poak at mi/z =58 or at m/ z=86 2.4-Dimethyl-3-pentanone does not have any y hydrogens. Therefore. it cannot undergo a Mclafferty rearrangement so it will not have a peak at 1/z=58 2.4-Dimethyl-3-pentanone will have a peak at m/z=58 doe to a McLatlerty rearrangament 4. Heptanere wi have a base peak at m/z=71. 2heptanone wel have a base peak at m/z=43 and 2,4 -dimethyh 3 -pentanone wie hire a base peak atm/z=71 2. Heptanone will have a peak at m/z=58 due to a Mel aflerty rearrangeraent 4.Heptanone wie have a peak at m/z=86 doe to a Mctafterty rearangement