Question
How do I calculate the molarity of Ce(NH4)2(NO3)6 using a given weight of the sample, needed to prepare 50.00 mL of a 5.500 x 10^-3
How do I calculate the molarity of Ce(NH4)2(NO3)6 using a given weight of the sample, needed to prepare 50.00 mL of a 5.500 x 10^-3 M solution?
We're preparing a weight sufficient for 50.00 mL of 5.500 x 10^-3 M solution, that weight is 0.151g of Ce(NH4)2(NO3)6
What would be the molarity of Ce(NH4)2(NO3)6 using this measured weight?
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Fundamentals Of Analytical Chemistry
Authors: Douglas A. Skoog, Donald M. West, F. James Holler, Stanley R. Crouch
10th Edition
0357450396, 978-0357450390
