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How do I show the work for these problems. elle 9th period Mendoza (p Hg = 13600 kg/m3 , p air = 1.29 kg/m3 )
How do I show the work for these problems.
elle 9th period Mendoza (p Hg = 13600 kg/m3 , p air = 1.29 kg/m3 ) (1 atm = 1 x 105 Pa) Fluids Quiz Fluid at rest: fluid pressure: 1. What is the absolute pressure a) in atm, and b) in pascals, at the ocean floor 3800 meters beneath the surface where the Titanic wreckage lies? (p seawater = 1025 kg/m3) 1= Po + igh = latm + 1625 x 10 X 3800 105 atm 391 atm : 100608 + 1025 X10 x 3800 Pa = 3.91 x 104 Pa 2. Intravenous infusion often uses gravity. Assuming the fluid density is 1000 kg/m3, and density of mercury is 13600 kg/m3, at what height h (from the top of the fluid to the needle entering the vein) should the bottle be placed so the liquid pressure is at 50 mm-Hg? 3. The gauge pressure in each of the four tires of an automobile is 2.5 atm. If each tire has a "footprint" of 0.025 m2, estimate the mass of the car. 4. How high would the level be in a barometer if the atmospheric pressure is 0.7 atm and the fluid in the barometer has a density of 1500 kg/m3? 5. Water needs be pumped to the top of a 250-m high building. What gauge pressure is needed in the water line at the base of the building to raise the water to this height?(p Hg = 13600 kg/m' , p air = 1.29 kg/m3 ) (1 atm = 1 x 105 Pa) 6. An open-tube manometer is used to measure the pressure of a confined gas as shown on the right. Find the pressure of the confined gas for a) and b) in Pascals. a) b ) Pa = Po + Pgh 10cm 1ocm Pg = Pugh P =? Hg P = ? Hg ( 13600 ( 10 ) (1 ) ) + 1 x 165 P + Poh P = 1x 165 - Pgghg Fluid at rest: Pascal's principle: 7. In a hydraulic lift, the diameters of the pistons are 0.1 m and 0.5 m. A car weighing 12000N is to be lifted by the force of the large piston. a) What force is to be applied to the small piston? b) When the small piston is pushed down by 0.02 m, how far is the car lifted? 8. The two pistons shown have radii of 0.2 m and 0.08 m. In the absence of friction, determine the force, F, required to support the 600-kg load. LoadStep by Step Solution
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