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1. The figure on the right shows several states in 1(%) Logft 154Gd populated in the decay of 154 0. 0086 11.733 (4+) -1788.8 a. What sort of decay is this? (1 pt). 28.60 8.659 2- 740.9 1719.6 1.584 10.398 3- 38.1071.2 1417.988.2-1617.1 0.320 11.405 2+ 1665.8301.4 1531.3 26 203.4305.2 36.3 9.740 2- 5 213 322.1_1397.5 > > > >:: 142319 467.9 1:342478.2 b. What particle(s) with mass are emitted in the 4 591. 8 1241.3. 1:723.369.5 decay (1 pt)? 16.8 10.659 3+ 80. 4 / 904.12 1,6 1127.8 13 1596.5: 18 3.5 11.57 Lord 246. 1 996.3 $1.14940.3 0.7 12.5 2+ 1621001408.35 134.9 873.1531.3 0+ 444. 5 1996.3 680.6 - . . . . . . . . 557.692.4 815. c. Which of these states is the most similar to the ground state of 63 154Eu? How did you 0.19 13.64 4+ 7 371 . - - 40 PS . . . . - 247.9 come to this conclusion (2 pts.) 10.0 12.16 2+ # # 123.1 - 1.184 NS 123.1 0+ YO . . ... STABLE . .. 646090 d. What is the energy, type and multipolarity of the 247.9 kev transition de-exciting the J"=4* level at 371 kev? (1 pts.). e. What lifetime would you estimate for the J"=2* level at 123.1 keV if it decayed via a 157 Weisskopf unit transition (2 pts.)? f. (Extra Credit) Use you answer from part f above and the info in the level scheme to determine the internal conversion coefficient of the 123.1 kev transition from the J"=2+ level. (2 pts.)CONSTANTS CO. Speed of light 2.99792458 x 108 m/s Charge of electron 1.602189 x 10-19 C Boltzmann constant 1.38066 X 10-23 J/K 8.6174 X 10 -5 eV/K Planck's constant h 6.62618 X 10-34 J . S 4.13570 x 10 -15 e eVS . h= h/2n 1.054589.X 10 34.J 34 . J. 6.58217 x 10-16 eV . s Gravitational constant G 6.6726 X 10-11 N . m2 /kg2 Avogadro's number NA 6.022045 x 1023 mole -1 Universal gas constant K 8.3144 J/mole . K Stefan-Boltzmann constant 5.6703 X 10-8 W/m2 . K4 Rydberg constant 1.0973732 x 10' m-1 Hydrogen ionization energy 13.60580 eV Bohr radius do 5.291771 x 10-11 m Bohr magneton P B 9.27408 X 10-24 J/T 5.78838 X 10-eV/T Nuclear magneton 5.05084 X 10-27 J/T 3.15245 x 10-8 eV/T Fine structure constant 1/137.0360 hc 1239.853 MeV . fm hc 197.329 MeV . fm e 2/4 TIED 1.439976 MeV . fm PARTICLE REST MASSES MeV/c2 Electron 5.485803 X 10-4 0.511003 Proton 1.00727647 938.280 Neutron 1.00866501 939.573 Deuteron 2.01355321 1875.628 Alpha 4.00150618 3727.409 0.1498300 139.5669 0.1448999 134.9745 0.1134292 105.6595 CONVERSION FACTORS 1 e.V = 1.602189 X 10-19 J 1 b = 10-28 m2 1 u = 931.502 MeV/c2 1 Ci = 3.7 x 1010 decays/s = 1.660566 X 10-27 kgShow your work and explain your reasoning clearly. You are allowed one page of notes (both sides). PLEASE WRITE YOUR STUDENT ID ON ALL PAGES! PLEASE PUT THE PROBLEM # ON TOP OF ANY ADDITIONAL SHEETS YOU USE! Group - 1 2 7 9 10 11 12 13 15 16 17 18 Period 2 I He 4 10 Be N O Ne 11 12 14 15 16 18 Na Ma Al 5 Ar 19 20 21 23 24 25 26 27 28 29 30 31 32 33 34 35 36 ca Sc V Cr Mn Fe Co Ni Cu Zn Ga Ge AS Se Kr 38 39 40 43 45 46 48 49 50 TC 52 53 54 Rb Sr Zr Nb Mo To Ru 3h Pd Ag Cd In Sn sb Te Xe 56 12 76 78 79 80 81 32 84 86 CS Ba Hf Ta W Re Os pt Au Ha TI Ri Po At Rn 87 88 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 Ra Rf Db Sq HS Mt DS Rg En Mh Mc LV TS Og Lanthanides 57 58 59 60 62 63 64 65 66 67 68 69 70 71 La Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Actinides 89 90 91 93 94 95 96 9 98 99 100 101 102 103 Ac Th Pa Np Pu Am Cm BK Cf ES Fm Md No Lr (E1) = 1.0 x 1014 A2/3 E3 MIC 1(E2) = 7.3 x 107 A4/3E5 Atotal = Ay (1 + a); a = (E3) = 34 A2 EZ Feather's Rule: (E4) = 1.1 x 10-5 A8/3 E9 Energy (MeV) Range (cmz) = 2 1(E5) = 2.4 x 10-12 A10/3 E11 A(M1) = 5.6 X 1013 E3 Bragg-Kleeman Rule: 2(M2) = 3.5 x 107 A2/3 E5 R1 _ P2 VA1 2(M3) = 16 A4/3 EZ R2 P1 VA 2 2(M4) = 4.5 x 10-6 ARE9 2(M5) = 7.4 x 10-13 A8/3611 At = 8 sing