Question: yellow boxes NAME Suppose you administer a certain aptitude test to a random sample of 9 students in your school, and that the average A

1 2 NAME 3 A new sneaker claims that it can make

yellow boxes

NAME Suppose you administer a certain aptitude test to a random sample of 9 students in your school, and that the average A new sneaker claims that it can make male athletes jump higher. A You are testing whether students at your school are score is 105. We want to determine the mean u of the sample of 25 male athletes is asked to jump once with their own sneakers overweight. You sample 25 students and measure how much population of all students in the school. Assume a standard in on and once wearing the new sneakers. The average jump increased by more they weigh than the average weight for their height. The deviation of G. = 15 for the test. Perform a 99% Cl and 1.5 inches with the new sneakers! Assume that o = 3. Find a 95% mean of your sample is 5 lbs, and we know that o = 5. Find a Interpret. confidence interval and interpret. 90% Confidence Interval and interpet. FIND YOUR POINT ESTIMATOR FIND YOUR POINT ESTIMATOR FIND YOUR POINT ESTIMATOR x x CHOOSE YOUR Z VALUE CHOOSE YOUR Z VALUE CHOOSE YOUR Z VALUE Z = 1,96 Z = 1.645 Z= 2.576 CALCULATE SIGMA CALCULATE SIGMA CALCULATE SIGMA o/Vn o/Vn a/Vn CALCULATE MARGIN CALCULATE MARGIN CALCULATE MARGIN 19 ME = Z*0/Vn ME =Z+0/Vn ME =2*ofvn

1 2 NAME 3 A new sneaker claims that it can make male athletes jump higher. A 4 sample of 25 male athletes is asked to jump once with their own sneakers 5 on and once wearing the new sneakers. The average jump increased by 6 1.5 inches with the new sneakers! Assume that =3. Find a 95% 7 confidence interval and interpret 8 FIND YOUR POINT ESTIMATOR 9 X 10 11 CHOOSE YOUR Z VALUE 12 Z= 13 1.96 14 CALCULATE SIGMA 15 0/Vn 16 17 18 CALCULATE MARGIN 19 ME-Z a/Vn 20 You are testing whether students at your school are overweight. You sample 25 students and measure how much more they weigh than the average weight for their height. The mean of your sample is 5 lbs. and we know that = 5. Find a 90% Confidence Interval and interpet. FIND YOUR POINT ESTIMATOR S CHOOSE YOUR Z VALUE Z= 1.645 CALCULATE SIGMA o/n CALCULATE MARGIN ME=Z*o/Vn Suppose you administer a certain aptitude test to a random sample of 9 students in your school, and that the average score is 105. We want to determine the mean of the population of all students in the school. Assume a standard deviation of o.15 for the test. Perform a 99% CI and Interpret. FIND YOUR POINT ESTIMATOR 2.576 CHOOSE YOUR Z VALU Z= CALCULATE SIGMA a/Vn CALCULATE MARGIN ME=2*0/Vn

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