Question
HOW DO YOU SOLVE THIS PROBLEM ON EXCEL? 1. The solution of LP2 should have subtours with multiple arcs.(If instead you get a solution with
HOW DO YOU SOLVE THIS PROBLEM ON EXCEL?
1. The solution of LP2 should have subtours with multiple arcs.(If instead you get a solution with more arcs with values greater than 1, then add constraints to eliminate these.)The fun (and somewhat time-consuming) part of the project is using the arcs whose values are equal to 1 to identify the subtours in your solution (e.g. if the first arc = 1, then a tour goes directly from Atlanta to Baltimore). Identifying the positive decision variables and connecting the corresponding cities will reveal the subtours that make up the solution to LP2.Find the smallest of these subtours and add a constraint to eliminate it.
For example: if cells D2, D3 and D14 all equal 1, this would give a subtour from Atlanta to Baltimore (D2) to Birmingham (D14) and back to Atlanta (D3). You would eliminate this by putting the formula =D2+D3+D14 into a cell on your spreadsheet, say G15, and then adding the constraint G15Specify the smallest subtour that you found by listing the 3 cities included in this tour (similar to the one in the example above: Atlanta to Baltimore to Birmingham to Atlanta, except that the 3-city subtour that you find makes geographic sense!).
Subtour:
2. Create a constraint to eliminate the subtour identified in the previous question and re-solve the LP relaxation. Give the optimal objective function of the new LP (LP3).
Optimal objective function value of LP3:
3. Repeat the process you just stepped through to identify the smallest subtour from LP3 (it should be similar to the one you just eliminated, but with 4 cities included instead of 3). Add a constraint to eliminate this subtour (since it has 4 cities, your constraint should require that the sum of the 4 arcs in the subtour must be). List the arcs in this subtour. After adding the new constraint, solve the resulting LP (LP4) and record its objective function value.
Arcs in subtour of LP3:
Optimal objective function value of LP4:
4. Repeat question 3 two more times. You should find two subtours that are very similar to the one you identified in the previous question. In fact, they should connect the same 4 cities. Identify the similar subtour in LP4 (by listing its arcs), add the constraint to eliminate it, and record the objective function value of LP5. Do the same thing to identify a subtour in LP5, eliminate it, and give the objective function value of the resulting LP6.
Arcs in subtour of LP4:
Optimal objective function value of LP5:
Arcs in subtour of LP5:
Optimal objective function value of LP6:
5. Considering the similarities of the previous three subtours that you had to eliminate one at a time, develop a better constraint (and a better approach) that could eliminate all of the subtours connecting the same 4 cities all at once?
6. The point of the previous question is that a single constraint could eliminate all subtours connecting the same 4 cities. Sadly, the total number of possible subtour constraints is combinatorial.How many sets of 4-city groupings would there be out of 13 total cities? This number might not seem so huge. But it ramps up quickly. How many sets of 10-city groupings would there be for a TSP with 100 total cities?
7. See if you can find the optimal solution to the 13-city TSP by continuing to eliminate subtours. After solving LP6, all that should be needed is to identify arcs whose LP6 solution value equals 2 and add the constraints to ensure they are. See what you can come up with as your best tour, either by continuing to add subtour constraints or by building one yourself using what you have learned from the LP solutions. Provide the tour (e.g Atlanta to Birmingham to ...), along with its associated costs.
1 Cities 2 Atlanta 3 Baltimore 4 Birmingham 5 Charleston WV 6 Greensboro 7 Jackson MS 8 Jacksonville 9 Memphis 10 Myrtle Beach 11 Nashville 12 Norfolk 13 Philadelphia 14 Washington DC 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 A 75 76 77 78 79 80 B Objective Atl-Balt Atl-Birm Atl-CharWV Atl-Green Atl-JackMS Atl-Jville Atl-Mem Atl-Myrtle Atl-Nash Atl-Norf Atl-Phil Atl-Wash Balt-Birm Balt-CharWV Balt-Green Balt-JackMS Balt-Jville Balt-Mem Balt-Myrtle Balt-Nash Balt-Norf Balt-Phil Balt-Wash Birm-CharWV Birm-Green Birm-JackMS Birm-Jville Birm-Mem Birm-Myrtle Birm-Nash Birm-Norf Birm-Phil Birm-Wash CharWV-Green CharWV-JackMS CharWV-Jville CharWV-Mem CharWV-Myrtle CharWV-Nash CharWV-Norf CharWV-Phil CharWV-Wash Green -JackMS Green-Jville Green-Mem Green-Mrytle Green-Nash Green-Norf Green-Phil Green-Wash JackMS-Jville JackMS-Mem JackMS-Myrtle JackMS-Nash JackMS-Norf JackMS-Phil JackMS-Wash Jville-Mem Jville-Myrtle Jville-Nash Jville-Norf Jville-Phil Jville-Wash Mem-Mrytle Mem-Nash Mem-Norf Mem-Phil Mem-Wash Mrytle-Nash Mrytle-Norf Mrytle-Phil Mrytle-Wash Nash-Norf Nash-Phil Nash-Wash Norf-Phil Norf-Wash Phil-Wash 2990 0 1 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 1 E 682 Atlanta 146 Baltimore 502 Birmingham 332 Charleston WV 380 Greensboro 346 Jackson MS 379 Jacksonville 362 Memphis 248 Myrtle Beach 558 Nashville 780 Norfolk 637 Philadelphia 780 Washington DC 361 355 1017 744 914 477 703 248 98 39 564 478 237 434 234 508 192 715 880 744 245 801 642 597 429 388 403 466 362 713 456 675 214 464 236 431 309 590 209 743 414 948 1115 980 677 358 596 613 844 706 752 212 898 F City Constraints 1014 879 589 339 571 432 688 802 666 290 209 137 G 2 2 2 2 2 2 2 2 2 2 2 2 2
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